FREE TEACHING LAB · 35 MINUTES · AGES 13 AND UP

When does interest start earning interest?

Compare simple and compound interest and explain how the same growth can help a saver or increase an unpaid debt.

Start with a fictional $1,000 balance. Interest is added once at the end of each year at a constant rate. There are no deposits, withdrawals, repayments, fees, taxes, or defaults. Read the ending balance as savings owned, or as debt owed if all interest is capitalized and no payments are made.

Use the terms precisely.

Principal
The starting amount saved or borrowed.
Simple interest
Interest calculated only on the original principal: P × r × years.
Compound interest
Interest added to the balance earns or accrues further interest: ending balance = P × (1 + r)^years.
Interest rate versus APR
A quoted interest rate alone may omit costs. APR is a broader borrowing-cost measure; this simplified model does not calculate a regulated APR.
Student worksheet

Work through the starting example.

These questions use the default settings, even if you changed the interactive lab. Show your calculations and explain one assumption behind your answer.

Starting inputs: Starting balance: $1,000; Annual interest rate: 8%; Years: 5 years.

Name: __________________________ Date: ______________

  1. At the defaults, calculate the compound balance after one year and after five years.
  2. Compare the five-year compound balance with simple interest. How much is due to compounding beyond simple interest?
  3. Reset, then set the rate to 0%. Explain both results. Why would a loan with monthly repayments behave differently from this model?

Try a new case

Compare 10 and 20 years at the same rate. Does doubling time double the interest? Use the figures to support your answer.

Exit ticket

What changed, what stayed fixed, and which term helps explain the result?

A 35 minute teaching plan

Use 5 minutes to introduce the question and vocabulary, 10 to predict and test inputs in pairs, 12 for the worksheet, 5 to compare explanations, and 3 for the exit ticket. Without devices, use the printed starting case and calculate changes by hand.

Look for a correct calculation, precise terminology, and an explanation that respects the model’s limits. For the open challenge, accept different cases when the arithmetic and reasoning support them.

Open teacher answer key
  1. Year 1: 1000 × 1.08 = $1,080. Year 5: 1000 × 1.08^5 = $1,469.33, including $469.33 of interest.
  2. Simple ending balance = 1000 × (1 + 0.08 × 5) = $1,400. Compounding adds $69.33 beyond simple interest.
  3. Both balances remain $1,000 at zero interest. Loan repayments reduce the outstanding balance; interest timing, fees, and contract terms also matter. The no-payment model does not represent a normal amortizing loan.

Teacher answer key: Interest, saving & borrowing

  1. Year 1: 1000 × 1.08 = $1,080. Year 5: 1000 × 1.08^5 = $1,469.33, including $469.33 of interest.
  2. Simple ending balance = 1000 × (1 + 0.08 × 5) = $1,400. Compounding adds $69.33 beyond simple interest.
  3. Both balances remain $1,000 at zero interest. Loan repayments reduce the outstanding balance; interest timing, fees, and contract terms also matter. The no-payment model does not represent a normal amortizing loan.

For the challenge and exit ticket, credit correct calculations, a clearly stated assumption, and precise use of a relevant term. Different supported examples are acceptable.

Where the model stops

These are mathematical scenarios, not promised savings returns or loan quotes. Many debts use different accrual rules and require regular payments.

Further reading: CFPB: how compound interest works. These fictional activities are original to World Economy. Reference links do not imply endorsement.

World Economy · losttofound.org/classroom/labs/compound-interest. An adult educator may print or privately share this free activity with their own learners. Keep the source attached. No resale or public rehosting.